A,b,c are three positive integers and 2s = a + b+ c.If(s – a):(?

a,b,c are three positive integers and 2s = a + b+ c.If(s – a):(s –b):(s – c) = 1:7:4,then the ratio a:b:c is-





"give calculation process"

A,b,c are three positive integers and 2s = a + b+ c.If(s – a):(?
2s = a + b + c





(s-a):(s-b):(s-c) = 1:7:4





from the ratio equation there, we know...





s - a = 1 which becomes a = s - 1


s - b = 7 which becomes b = s - 7


s - c = 4 which becomes c = s - 4





Plug those into the


2s = a + b + c equation to find s.





2s = (s - 1) + (s - 7) + (s - 4)


2s = 3s - 12


2s + 12 = 3s


12 = s





So....


a = s - 1 = 12 - 1 = 11


b = s - 7 = 12 - 7 = 5


c = s - 4 = 12 - 4 = 8





So...


a:b:c: = 11:5:8
Reply:2s = a + b + c


(s-a):(s-b):(s-c) = 1:7:4





Therefore


s - a = 1


hence a = s - 1


s - b = 7


hence b = s - 7


s - c = 4


hence c = s - 4





substituting these values in the equation


2s = a + b + c


2s = (s –1) + (s – 7) + (s – 4)


2s = 3s – 12


2s + 12 = 3s


12 = s


Then


a = s – 1 = 12 – 1 = 11


b = s – 7 = 12 – 7 = 5


c = s – 4 = 12 – 4 = 8


Putting these values in the ratio,


a:b:c: = 11:5:8
Reply:take a look the link to solve ur problem. it's a kind of heron's formula.





hope can help u.


thanks
Reply:a:b:c is 11:5:8





s-a=1,s-b=7, s-c=4


a+b+c=2s =%26gt; s-1 + s-7 +c= 2s


c=8


s=12


b=5


a=11
Reply:The first two answers are superb..follow them and get your problem solved...... :))
Reply:2s = a + b + c


(s-a):(s-b):(s-c) = 1:7:4





Therefore


s - a = 1


hence a = s - 1


s - b = 7


hence b = s - 7


s - c = 4


hence c = s - 4





substituting these values in the equation


2s = a + b + c


2s = (s –1) + (s – 7) + (s – 4)


2s = 3s – 12


2s + 12 = 3s


12 = s


Then


a = s – 1 = 12 – 1 = 11


b = s – 7 = 12 – 7 = 5


c = s – 4 = 12 – 4 = 8


Putting these values in the ratio,


a:b:c: = 11:5:8

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