This is not my homework..I have to know how to do this inorder to do my project next week..Just trying to get a head start!!
Write a function
void sort3(int%26amp; a, int%26amp; b, int%26amp; c) {
}
that sorts three numbers in ascending order. For example,
int a=8;
int b=10;
int c=4;
sort3(a,b,c);
printf(‘‘small: \%d, middle: \%d, large: \%d\n’’,a,b,c);
should have output:
smallest: 4, middle: 8, largest: 10
C++ help please!!?
Assume you want the "sort" function to do the sorting and not just print the info. This routine will perform a simple sort and can be expanded very easily.
void sort(int a, int b, int c) {
int mynums[3], x, y, tmp;
mynums[0]=a;
mynums[1]=b;
mynums[2]=c;
for (x=0; x%26lt;2; x++) {
for (y=x+1; y%26lt;3; y++) {
if (mynums[x] %26gt; mynums[y]) {
tmp=mynums[x];
mynums[x]=mynums[y];
mynums[y]=tmp;
}
}
}
a=mynums[0];
b=mynums[1];
c=mynums[2];
}
Reply:I don't know if this is what your instructor had in mind (probably he wanted you to implement the sorting yourself). But I will post my solution anyway. It uses the STL sort algorithm.
#include %26lt;algorithm%26gt;
using namespace std;
void sort3(int %26amp;a, int %26amp;b, int %26amp;c) {
int num[3];
num[0] = a;
num[1] = b;
num[2] = c;
sort(%26amp;num[0], %26amp;num[3]);
a = num[0];
b = num[1];
c = num[2];
}
int main() {
int a = 4, b = 10, c = 6;
sort3(a, b, c);
}
Reply:void sort3(int a, int b, int c)
{
IF (a %26lt; b) THEN
IF (a %26lt; c) THEN
IF (b %26lt; c) THEN
printf( a, b, c)
ELSE
printf( a, c, b)
END IF
ELSE
printf(c, a, b)
END IF
ELSE
IF (b %26lt; c) THEN
IF (a %26lt; c) THEN
printf( b, a, c)
ELSE
printf( b, c, a)
END IF
ELSE
printf(c, b, a)
END IF
END IF
}
int a=8;
int b=10;
int c=4;
sort3(a,b,c);
hope this will solve your problem, if you still have any problem you can reach me at asim_developer@yahoo.com
or i will be online at asimhero2003@yahoo.com
Thanks
Asim
cvs
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment